If you want to multiply any number with 9, 99, 999, so on
Consider the following examples
Example 1
99 X 42 = 4158
Procedure
Step 1 Subtract 1 from 42, we get 41
Step 2 Now, Subtract 41 from 99, we get 58
Answer is 4158
Example 2
999x343=342657
Procedure
Step 1 343 – 1 = 342
Step 2 9-3 = 6, 9-4 = 5, 9-2 = 7
Answer is 342657
Showing posts with label Vedic Mathematics. Show all posts
Showing posts with label Vedic Mathematics. Show all posts
Friday, 19 October 2007
Monday, 3 September 2007
Sutra 1
I am sharing one example where this sutra is applied.
Finding the square of a number ending with 5.
65^2
= [6 X (6+1)] 25 = 4225
For this number , the last digit is 5 and the 'previous' digit is 6. Hence, 'one more than the previous one', that is, 6+1=7.
The Sutra, in this context, gives the procedure 'to multiply the previous digit 6 by one more than itself, that is, by 7'. It becomes the L.H.S of the result, that is, 6 X 7 = 42. The R.H.S of the result 25.
85^2
= [8 X (8+1)] 25 = 7225
For this number , the last digit is 5 and the 'previous' digit is 8. Hence, 'one more than the previous one', that is, 8+1=9. The Sutra, in this context, gives the procedure 'to multiply the previous digit 8 by one more than itself, that is, by 9'. It becomes the L.H.S of the result, that is, 8 X 9 = 72. The R.H.S of the result 25.
Saturday, 1 September 2007
Vedic Mathematics
Vedic Mathematics is the ancient system of Mathematics which was rediscovered from the Vedas between 1911 and 1918 by Sri Bharati Krisna Tirthaji (1884-1960).
According to his research all of mathematics is based on sixteen Sutras or word-formulae.
According to his research all of mathematics is based on sixteen Sutras or word-formulae.
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